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Thanks for any and all help and advice!!

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Joined

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380 Posts

Thanks for any and all help and advice!!

Joined

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5,554 Posts

You have a 16ohm load in parallel with and 8 ohm load, the 8 ohm load will get the bulk of the power. (P=Esquared/R), in this case the E will be constant to both cabs. (the 8 ohm cab will always get double the power the 16 ohm cab gets when they are in parallel)

Worse still, the 8 ohm load has only 2 speakers in it. So that 8 ohm cab will get more than 1/2 the total power which will then be shared between the 2 twelves in it.

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12,970 Posts

Very good point, sir. Especially considering the OP is a SunnO))) fan, and I believe they celebrate loudness. Go easy on it, @danielSunn0))) , that 212 will be taking about 66% of the total power, so each speaker in that cab will be dissipating the same amount of power as the whole 412 cab will (about 33% of total power).

You have a 16ohm load in parallel with and 8 ohm load, the 8 ohm load will get the bulk of the power. (P=Esquared/R), in this case the E will be constant to both cabs. (the 8 ohm cab will always get double the power the 16 ohm cab gets when they are in parallel)

Worse still, the 8 ohm load has only 2 speakers in it. So that 8 ohm cab will get more than 1/2 the total power which will then be shared between the 2 twelves in it.

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