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I have an Allen Accomplice it supports either 6V6 or 6L6 tubes. If 6V6 are in it the ohm switch is a 8\16 ohms setting. For 8 ohm speakers use 8 ohm setting. For 16 ohm speaker use 16 ohm.

If, however you are using 6L6 tubes, which I am, the ohm switch becomes 4\8 ohm. 8 ohm speaker use the 4 ohm setting, 16 ohm speaker use the 8 ohm setting. These instructions are marked on the back this way and the amp is designed this way.

The speaker extension jack is wired in parallel. I have an 8 ohm speaker in the combo. If I connect a cabinet with an 8 ohm speaker, do I still use the 4 ohm setting or is 2X8 ohms too much load? Like does it split it down to 2 ohms? I am not sure how series and parallel work so just wanted confirmation.

2 speakers 8 ohm would normally be 16 ohms divided by 2 for an 8 ohm setting. but with this amp the way it works I'm thinking it would be 4 ohms.

I did send an email to David Allen but mistakenly thought the amp had a 16 ohm speaker and that is what I told him. This was his answer. So now that I found out that the internal speaker is actually 8 ohms and I should match the extension cabinet with an 8 ohm speaker it seems I should be using the 4 ohm tap. But just want to be sure I'm not missing anything.

If you could use a 16 ohm extension speaker cabinet along with your internal 16 ohm combo speaker, then the amp would see those two in parallel or 8 ohms. In that case your amp would be matched with the impedance switch set for 8 ohms (up). It would also divide the power equally if each is 16 ohms.

David