PDA

View Full Version : Easy impedence question

kat_
03-24-2007, 10:36 PM
Would two 8ohm speakers wired in series be 16 ohms or 4?
Adicted to Tubes
03-24-2007, 10:54 PM
Two 8 ohm speakers wired in series would be 16 ohms.Wired parallel they are 4 ohms.
kat_
03-24-2007, 10:58 PM
Excellent, thank you.

I got an old 2x12 cab from a neighbour who doesn't play anymore so I'm trying to get to know it a bit.
PaulS
03-25-2007, 12:02 AM
Yep, in series you add them up and in parallel you divide by the number of speakers used, assuming they are the same rating.
Scottone
03-25-2007, 12:48 PM
Yep, in series you add them up and in parallel you divide by the number of speakers used, assuming they are the same rating.

The formula for parallel is:

R (total) = (R1 * R2)/(R1 + R2) just in case you have to work out two speakers with different impendances.
Wild Bill
03-25-2007, 01:09 PM
The formula for parallel is:

R (total) = (R1 * R2)/(R1 + R2) just in case you have to work out two speakers with different impendances.

Remember if they are different impedances the lower impedance hogs the power, big time!
kat_
03-25-2007, 09:16 PM
Thanks for all of the info guys. I haven't decided what I want to do with this little cab yet. It doesn't sound bad, but it's nothing special. I don't really have any use for it, but it's probably not worth enough to bother selling either. I guess it'll sit around until I need it for something.